• Sw2244
    0
    Hi, im totally new to uw, but have a 4th Ed book by Pozar and am slowly plowing through it. I have an Elec Eng degree but been out if it for years doing IT, so Im learning a lot of this from scratch as a hobby.

    My question is with a WR430 waveguide, for calculating where 1/4 wavelength locations should be along the waveguide - should i use the free air wavelength, or use the lamdba g ( waveguide wavelength)?
  • UnknownEditor
    4
    I believe you should use lambda guide, as described here

    https://www.microwaves101.com/encyclopedias/waveguide-mathematics

    But I would hold out for a second opinion!

    Steve
  • teleko7
    0
    Hi
    Agreeing with the previous answer and from what I've learned, I would say wavelength in a waveguide is modified with regards to the wavelength in an unbounded medium by the m and n indexes of the mode that you consider, as the propagating wave is not a perfect plane wave unless you go very high in frequency...

    You can also check your Pozar(MWEng, 4ed. p112), Balanis(Adv.Eng.Electromags,1ed. p354) or Ramo (Fields&Waves in CommElectr, 3ed. p418) or go to the classics: Marcuvitz (WaveguideHandbook, Ch1)

    Hope this helps.

    Regards

    Iban
  • Antonio
    0
    Also, from Feynman lectures, which are very easy to read through, you can see it´s in line with Microwaves101: see formula (24.19), you can find the lecture on this link http://www.feynmanlectures.caltech.edu/II_24.html
  • Aparna Bhuvanagiri
    0
    You need to use lambda g which is the wave length inside the wave guide for a particular frequency
bold
italic
underline
strike
code
quote
ulist
image
url
mention
reveal
youtube
tweet
Add a Comment

Welcome!

Join the international conversation on a broad range of microwave and RF topics. Learn about the latest developments in our industry, post questions for your peers to answer, and weigh in with some answers if you can!